How do you write #f(x) = 3x^2 + 6x + 1# in vertex form?
1 Answer
Aug 24, 2017
Explanation:
Complete the square:
#f(x) = 3(x^2 + 2x + m - m) + 1#
To find
#f(x) = 3(x^2 + 2x + 1- 1) + 1#
#f(x) = 3(x^2 + 2x + 1) - 3 + 1#
#f(x) = 3(x + 1)^2 - 2#
Hopefully this helps!
