Question

How do you write `f(x) = 3x^2 - 6x + 9` into vertex form?

Answer 1

`y = 3(x - 1)^2 + 6`

Explanation:

x-coordinate of vertex:
`x = -b/(2a) = 6/6 = 1`
y-coordinate of vertex:
y (1) = 3 - 6 + 9 = 6
Vertex (1, 6)
Vertex form
`y = 3(x - 1)^2 + 6`