# How do you write the equation of the parabola in vertex form given vertex (0,0) and the directrix y=-16?

##### 1 Answer

Jul 2, 2017

#y=1/64 x^2#

#### Explanation:

Given -

Vertex

Directrix

Focus

The Parabola is opening up, as its directrix is

The formula for the parabola in the vertex form is -

#(x-h)^2=4.a.(y-k)^2#

Where -

#h = 0# x-coordinate of the vertex

#k=0# y-coordinate of the vertex

#a=16# distance between vertex and focus

#x-0)^2=4xx16(y-0)#

#x^2=64y#

#y=1/64 x^2#