# How do you write the equation y-5=6(x+1) in slope intercept form?

Jun 12, 2017

See a solution process below:

#### Explanation:

The slope-intercept form of a linear equation is: $y = \textcolor{red}{m} x + \textcolor{b l u e}{b}$

Where $\textcolor{red}{m}$ is the slope and $\textcolor{b l u e}{b}$ is the y-intercept value.

First, expand the terms in parenthesis on the right side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:

$y - 5 = \textcolor{red}{6} \left(x + 1\right)$

$y - 5 = \left(\textcolor{red}{6} \times x\right) + \left(\textcolor{red}{6} \times 1\right)$

$y - 5 = 6 x + 6$

Now, add $\textcolor{red}{5}$ to each side of the equation to solve for $y$ while keeping the equation balanced:

$y - 5 + \textcolor{red}{5} = 6 x + 6 + \textcolor{red}{5}$

$y - 0 = 6 x + 11$

$y = \textcolor{red}{6} x + \textcolor{b l u e}{11}$