# How do you write the quadratic in vertex form given y=x^2+4x-7?

$y = {x}^{2} + 4 x - 7 = {\left(x + 2\right)}^{2} - 11$
In general, for $y = a {x}^{2} + b x + c$, the $x$ coordinate of the vertex is $- \frac{b}{2 a}$, and the vertex form is:
$y = a {\left(x + \frac{b}{2 a}\right)}^{2} + \left(c - {b}^{2} / \left(4 a\right)\right)$