# How do you write the quadratic in vertex form given y= x^2-6x+15?

Vertex form is written by completing the square in the equation. Here y=${x}^{2} - 6 x + 15$
=${x}^{2} - 6 x + 9 - 9 + 15$ { Half the coefficent of x and square it, then add and subtract that number]
= ${\left(x - 3\right)}^{2} + 6$
The equation is therefore y-6= ${\left(x - 3\right)}^{2}$ which is in the required format. Vertex is (3,6)