How do you write the slope intercept form of the line #6x+5y=-15#?

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Answer 1 · 2017-01-27T23:31:39

#y = color(red)(-6/5)x - color(blue)(3)#

The slope-intercept form of a linear equation is:

#y = color(red)(m)x + color(blue)(b)#

Where #color(red)(m)# is the slope and #color(blue)(b)# is the y-intercept value.

We need to solve this equation for #y#:

#6x + 5y = -15#

#6x - color(red)(6x) + 5y = - color(red)(6x) - 15#

#0 + 5y = -6x - 15#

#5y = -6x - 15#

#(5y)/color(red)(5) = (-6x - 15)/color(red)(5)#

#(color(red)(cancel(color(black)(5)))y)/cancel(color(red)(5)) = (-6x)/5 - 15/5#

#y = -6/5x - 3#