# How do you write the trigonometric form into a complex number in standard form 8(cos((pi)/2)+isin((pi)/2))?

Feb 28, 2017

$8 \left(\cos \left(\frac{\pi}{2}\right) + i \sin \left(\frac{\pi}{2}\right)\right)$ in standard form is $0 + 8 i$.

#### Explanation:

$8 \left(\cos \left(\frac{\pi}{2}\right) + i \sin \left(\frac{\pi}{2}\right)\right)$

= $8 \cos \left(\frac{\pi}{2}\right) + 8 i \sin \left(\frac{\pi}{2}\right)$

= $8 \times 0 + 8 i \times 1$

= $0 + 8 i$

which is the complex number in standard form.