How do you write the vector equation that passes through point (-6,10) and parallel to <3,2>?

1 Answer
Aug 26, 2016

Answer:

#r = < x, y > =<3t-6, 2t+10>#

Explanation:

If a vector #V# is parallel to the vector #U#, then #V=t U#, where t is

a scalar.l

Let #r = < x, y ># be the position vector #OP# to the point P(x, y) on

the line through A(-6, 10) in the direction of #<3, 2>#. Then,

Vector #AP#

#= OP - OA#

# = < x+6, y-10 >#

# = t <3, 2 >#, .

So, # r = < x, y > = < 3t-6, 2t+10 >#