# How do you write the Vertex form equation of the parabola y = x^2-6x+8?

May 8, 2016

$y = {\left(x - 3\right)}^{2} - 1$

#### Explanation:

$y = {x}^{2} - 6 x + 8$
x-coordinate of vertex:
$x = - \frac{b}{2 a} = \frac{6}{2} = 3$
y-coordinate of vertex:
y(3) = 9 - 18 + 8 = -1
Vertex (3, -1)
Vertex form:
$y = {\left(x - 3\right)}^{2} - 1$