How do you write the vertex form equation of the parabola #y = (x - 3)^2 + 36#?

2 Answers
Oct 9, 2017

The vertex is #(3,36)#.

Explanation:

The vertex of parbola #y=(x-h)^2+k# is #(h,k)#. Comparing #y=(x-3)^2+36# with #y=(x-h)^2+k# we get #h=3 and k=36#

So the vertex is #(3,36)#.

Jan 2, 2018

#"in vertex form"#

Explanation:

#"the equation of a parabola in "color(blue)"vertex form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#

#"where "(h,k)" are the coordinates of the vertex and a"#
#"is a multiplier"#

#y=(x-3)^2+36larrcolor(blue)"in vertex form"#