Question

How do you write `y=-2x^2-2x-7` in vertex form?

Answer 1

`(y-(-13/2))=-2(x-(-1/2))^2`

Explanation:

`y=-2x^2-2x-7`

`=-2(x^2+x)-7`

`=-2(x^2+2xx1/2xx x+(1/2)^2-1/4)-7`

`=-2(x+1/2)^2+1/2-7`

`=-2(x+1/2)^2-13/2`

or `y=-2(x-(-1/2))^2-13/2`

or `(y-(-13/2))=-2(x-(-1/2))^2` and vertex is `(-1/2,-13/2)`

graph{-2x^2-2x-7 [-5.457, 4.543, -8.34, -3.34]}