How do you write #y= 4x^2 + 16x + 23# into vertex form? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Nghi N. May 13, 2015 #(-b/2a) = -16/8 = -2# #f(-b/2a) = f(-2) = 16 - 32 + 23 = 7# Factored form:# f(x) = 4(x + 2)^2 + 7# Check: Develop: #f(x) = 4(x^2 + 4x + 4) + 7 = 4x^2 + 16x + 23. #Correct Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 2934 views around the world You can reuse this answer Creative Commons License