# How many milliliters of 12.0 M hydrochloric acid (HCl) is required to prepare 0.75 L of a 0.25 M solution of HCl?

May 28, 2016

16mL

#### Explanation:

We have to use the titration formula:
${M}_{a} {V}_{a} = {M}_{b} {V}_{b}$
Now just plug it in.
$\left(12\right) \left(x\right) = \left(.75\right) \left(.25\right)$
$12 x = .1875$
$x = 0.015625$ liters
To convert liter to mL, multiply it by 1000, since 1 L= 1000 mL