# How many times does the graph of y = x + 1 intersect the graph of y = x^2 + 3?

Mar 25, 2018

They never intersect.

#### Explanation:

Let's solve the system and see!

$x + 1 = {x}^{2} + 3$

$0 = {x}^{2} - x + 2$

Now we apply the discriminant (the question asks how many solutions, not what they are).

$X = {b}^{2} - 4 a c$

$X = {\left(- 1\right)}^{2} - 4 \left(1\right) \left(2\right)$

$X = - 7$

Since $- 7 < 0$, this system has no real solutions--the graphs never intersect. We can confirm this by graphing both functions on the same grid.

Hopefully this helps!

Mar 25, 2018

the answer is no intersect between two equation

#### Explanation:

because intersect means that ther is same Y between $y = x + 1$
and $y = {x}^{2} + 3$ so if they intersect there is someting same y
so, lets think $x + 1$= ${x}^{2} + 3$ this eaquation could be ${x}^{2} - x + 2$ but we can't fint the $x$ and that means no same y from the insertion of the x

do you under stand?