# How to write the slope intercept form of the equation of the line passes through (-3,-2), and parallel y = x+2?

Jul 19, 2016

$y = x + 1$

#### Explanation:

As the equation $y = x + 2$ is already in slope intercept form, its slope is $1$ (coefficient of $x$).

Slopes of two parallel lines are equal and hence slope of line parallel to $y = x + 2$ is also $1$.

Now equation of line passing through $\left({x}_{1} , {y}_{1}\right)$ having a slope $m$ is

$\left(y - {y}_{1}\right) = m \left(x - {x}_{1}\right)$

Hence equation of line passing through $\left(- 3 , - 2\right)$ and slope $1$ is

(y-(-2))=1×(x-(-3)) or

$y + 2 = x + 3$ or $y = x + 1$ in slope intercept form.