# If 15 moles of water was made in this reaction, how many grams of carbon dioxide were made? H_2CO_3rarrH_2O+CO_2

Feb 12, 2018

$660.15 \text{g}$ of carbon dioxide was produced.

#### Explanation:

We have the equation ${H}_{2} C {O}_{3} \rightarrow {H}_{2} O + C {O}_{2}$.

The moles of water and carbon dioxide are in the ratio $1 : 1$.

So $15$ moles of water and $15$ moles of carbon dioxide are produced.

The formula for moles is $n = \frac{m}{M}$, where $m$ is the mass of the substance and $M$ its molar mass.

Rearranging the equation we get $m = n M$.

We have $15 \text{mol}$ of carbon dioxide and the molar mass of the gas is $44.01 \text{g"/"mol}$.

Inputting:

$m = 15 \cdot 44.01$

$m = 660.15 \text{g}$ of carbon dioxide was produced.