If a #10kg# object moving at #7 m/s# slows down to a halt after moving #5/2 m#, what is the friction coefficient of the surface that the object was moving over?

1 Answer
P dilip_k
Apr 6, 2016

considering conservation of mechanical energy
wirk done against frictional force = KE of the body
#mumgxxs=1/2mxxv^2#
#mu = v^2/(2gs)=7^2/(2xx9.8xx5/2)=1#

Related questions
See all questions in Frictional Forces
Impact of this question
1705 views around the world
You can reuse this answer
Creative Commons License