If an object is moving at 11 m/s over a surface with a kinetic friction coefficient of u_k=22 /g, how far will the object continue to move?

1 Answer
Jul 30, 2016

Considering the conservation of mechanical energy we can say that KE of the moving body is equal to the work done by it against the force of kinetic friction.If m represents mass and v the velocity of the moving object then

mu_kmgxxd=1/2mxxv^2 ,where d is the distance traversed.

=>d=v^2/(2mu_kg)=11^2/(2*22/g*g)=11/4=2.75m