# If sides A and B of a triangle have lengths of 9 and 7 respectively, and the angle between them is (3pi)/8, then what is the area of the triangle?

If the angle between two sides A,B be $\theta$ the area of the triangle will be = $\frac{1}{2} \cdot A \cdot B \cdot \sin \theta$
And $\theta = 3 \frac{\pi}{8}$
So area $= \frac{1}{2} \cdot 9 \cdot 7 \cdot \sin \left(3 \frac{\pi}{8}\right)$=29.10 squnit