# In triangle ABC, AC=10.4, CB=x andAB=12 (hypotenuse), how do you find BC, m<A, and m<B?

##### 1 Answer

Apr 25, 2015

Using the Pythagoras theorem,

let us consider a right angled triangle ABC, right angled at "C"

AB = 12

BC = 'x'

AC = 10.4

x =

BC = x = 5.98

calculating the angles:

AB = 12 = side "c"

BC = 5.98 = side "a"

AC = 10.4 = side "b"

by law of sines

a/Sin A = b/Sin B = c/Sin C

and by law:

so

B =

Similarly