In triangle ABC, how do you solve the right triangle given AB =4 , BC=1?
1 Answer
Nov 9, 2015
Explanation:
you would use the Pythagorean theorem
so given the hypotenuse (c) from AB=4 and side (a) as BC=1
you plug it into the formula to get:
1^2+b^2=4^2
you square the 1 and 4 and then subtract the 1 from 4 so you are left with the b^2 on one side
b^2=15
square root the 15 and get 3.87
