# In triangle ABC, how do you solve the right triangle given AB =4 , BC=1?

##### 1 Answer

Nov 9, 2015

#### Explanation:

you would use the Pythagorean theorem

so given the hypotenuse (c) from AB=4 and side (a) as BC=1

you plug it into the formula to get:

1^2+b^2=4^2

you square the 1 and 4 and then subtract the 1 from 4 so you are left with the b^2 on one side

b^2=15

square root the 15 and get 3.87