In triangle ABC, how do you solve the right triangle given side b=105m and side c=139m?

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Answer 1 · 2015-10-21T04:26:44

#a=91.08#

According to the Pythagorean theorem: #a^2+b^2=c^2#. The #c# given is #139#, the b given is #105#.
Plug the #139# for #c# and #105# for #b#,

We get
#a^2+105^2=139^2#

expand

#a^2+11025=19321#

Isolate the #a# by subtracting 11025 from both sides

#a^2 = 8296#

Now get #a#,

#a=sqrt8296#

#a=91.08#