Question

In triangle ABC, measure of angle A=32 a=12 and b=10, how do you find the measures of the missing angles and side of triangle A?

Answer 1

First find B and C. Use trig identity: `sin A /a = sin B/b`

`sin B = (b.sin A)/a = (10.(0.53))/12 = 0.44 -> B = 26.20`

`C = 180 - 32 = 26.20 = 121.08`

`c = (b.sin C)/sin B = (10.(0.86))/(0.44)` = 19.46