# To what volume must 440.0 mL of 3.50 M KNO_3 be diluted to produce 1.50 M KNO_3?

##### 1 Answer
Mar 5, 2017

${C}_{1} {V}_{1} = {C}_{2} {V}_{2}$

${V}_{2} = \text{ a bit over 1 litre}$

#### Explanation:

The product ${C}_{1} {V}_{1}$ has units of $m o l \cdot \cancel{{L}^{-} 1} \times \cancel{L} = m o l$, and thus it is dimensionally consistent.

And V_2=(C_1V_1)/C_2=(440.0*mLxx3.50*cancel(mol*L^-1))/(1.50*cancel(mol*L^-1))=??mL