# To what volume should you dilute 20 mL of a 12 M H_2SO_4 solution to obtain a 0.16 M H_2SO_4 solution?

Aug 14, 2016

${C}_{1} {V}_{1} = {C}_{2} {V}_{2}$.

A final volume of $1.500 \cdot L$ is required.

#### Explanation:

The product ${C}_{1} {V}_{1}$ is by definition the number of moles of stuff, which is fixed according to the volume and the concentration of your starting material.

We started with $20 \cdot m L$ of $12 \cdot m o l \cdot {L}^{-} 1$ $\text{sulfuric acid}$.

And thus $\frac{20 \cdot m L \times 12 \cdot \cancel{m o l \cdot {L}^{-} 1}}{0.16 \cdot \cancel{m o l \cdot {L}^{-} 1}} = {V}_{2} = 1500 \cdot m L$

PS When you do the dilution, do you add the acid to the water? Why?