Question

Two corners of a triangle have angles of `(5 pi )/ 8` and `( pi ) / 2`. If one side of the triangle has a length of `8`, what is the longest possible perimeter of the triangle?

Answer 1

Sum needs correction as two angles account for greater than `pi`

Explanation:

Given :
/_ A = (5pi)/8, /_B = pi / 2#

Sum of all the three angles must be = `pi`

`pi / 2 + ((5pi)/8) = ((9pi)/8)` which is greater than `pi`

As sum of the given two angles exceeds `pi`,
such a triangle cannot exist.