Two corners of an isosceles triangle are at #(1 ,7 )# and #(2 ,3 )#. If the triangle's area is #6 #, what are the lengths of the triangle's sides?

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Answer 1 · 2017-12-05T13:16:51

Measure of the three sides are (4.1231, 3.5666, 3.5666)

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Length #a = sqrt((2-1)^2 + (3-7)^2) = sqrt 17 = 4.1231#

Area of #Delta = 6#
#:. h = (Area) / (a/2) = 6 / (4.1231/2) = 6 / 2.0616 = 2.9104#

#side b = sqrt((a/2)^2 + h^2) = sqrt((2.0616)^2 + (2.9104)^2)#
#b = 3.5666#

Since the triangle is isosceles, third side is also #= b = 3.5666#