What are the components of the vector between the origin and the polar coordinate $(1, \frac{3 π}{8})$ $(1, (3pi)/8)$ ?

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Answer 1 · 2016-08-02T14:21:03

If $(r, θ)$ $(r,theta)$ be the polar coordinate of point then the position vector of the point is

$\to a = r cos θ ˆ i + r sin θ ˆ j$ $veca=rcosthetahati+rsinthetahatj$

$For r = 1 and θ = \frac{3 π}{8} \to a b e c o m e s$ $"For "r=1 and theta =(3pi)/8" "veca" becomes$

$\to a = 1 \cdot cos (3 \frac{π}{8}) i + 1 \cdot sin (3 \frac{π}{8}) j$ $veca=1*cos(3pi/8)i+1*sin(3pi/8)j$

$\to a = (0.38) i + (0.92) j$ $veca=(0.38)i+(0.92)j$

What are the components of the vector between the origin and the polar coordinate (1,3π8)(1, (3pi)/8)?