What are the components of the vector between the origin and the polar coordinate #(9, (-11pi)/6)#?
1 Answer
Feb 27, 2016
Explanation:
Using the formulae that links Polar to Cartesian coordinates.
#• x = rcostheta #
#• y = rsintheta # here r = 9 and
# theta = (-11pi)/6 # hence
# x =9cos((-11pi)/6)=9xx0.866 ≈ 7.794 # and
# y = 9sin((-11pi)/6) = 4.5 #
