Question

What are the components of the vector between the origin and the polar coordinate `(9, (-11pi)/6)`?

Answer 1

`((7.8),(4.5))`

Explanation:

Using the formulae that links Polar to Cartesian coordinates.

`• x = rcostheta`

`• y = rsintheta`

here r = 9 and `theta = (-11pi)/6`

hence `x =9cos((-11pi)/6)=9xx0.866 ≈ 7.794`

and `y = 9sin((-11pi)/6) = 4.5`