# When 20H combine with another 2OH would it form oh subscript 4?

Jul 15, 2017

If you're asking whether you get

color(red)(2"OH" + 2"OH" -> ("OH")_4)...

no, that doesn't make sense. ${\left(\text{OH}\right)}_{4}$ doesn't exist, because oxygen generally only makes two bonds at a time, and hydrogen generally only makes one bond at a time.

$\text{OH}$ is $\text{O"-"H}$, but ${\left(\text{OH}\right)}_{4}$ would be described by something like...

stackrel("H")stackrel(|)"O"-stackrel("H")stackrel(|)"O"-stackrel("H")stackrel(|)"O"-stackrel("H")stackrel(|)"O"

You should just get $4 \text{OH}$... meaning there is no reaction at all.