# What is the electron configuration for Fe_2?

Jun 16, 2017

The ion $F {e}^{2 +}$ electron configuration is $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 3 {d}^{6}$

#### Explanation:

The electron configuration for iron, $F e$ is $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 3 {d}^{6} 4 {s}^{2}$

The orbital filling order for $F e$ is $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 4 {s}^{2} 3 {d}^{6}$

Iron does not occur as $F {e}_{2}$ in nature. It is not a diatomic element.

The ion $F {e}^{2 +}$ electron configuration is $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{6} 3 {d}^{6}$.

It is missing the two valence electrons in the $4 {s}^{2}$ orbital. This makes the ion a cation, an ion that is positively charged because it has lost valence electrons.