What is the equation of the circle with a center at #(-1 ,-1 )# and a radius of #2 #?

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How do you write the general form given a circle that passes through the given points. P(-2, 0),...
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Answer 1 · 2016-03-01T15:05:51

#x^2+y^2+2x+2y-2=0#

As the points on the circle will be all at a distance of #2# from center at #(-1,-1)#, the equation will be

#(x-(-1))^2+(y-(-1))^2=2^2# or

#(x+1)^2+(y+1)^2=4# or

#x^2+2x+1+y^2+2y+1=4# or

#x^2+y^2+2x+2y-2=0#