What is the length of the hypotenuse of a right triangle if the two other sides are of lengths 6 and 2?

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Answer 1 · 2018-06-30T17:22:30

$2sqrt(10)$

By the Theorem of Pythagorean
$c^2=a^2+b^2$

we get

$c^2=4+36$
so
$c=sqrt(40)=sqrt(4*10)=2sqrt(10)$

Answer 2 · 2018-06-30T17:27:08

The length of hypotenuse $=c=2sqrt10~~6.32$

Let $triangle ABC$ be the right triangle.

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Let , $bar(AB)$ be the hypotenuse and $m /_C=pi/2$

Let , $BC=a=2 and AC=b=6 and AB=c$

We know that,

$c^2=a^2+b^2$

$=>c^2=2^2+6^2=4+36=40$

$=>c^2=4xx10$

$=>c=2sqrt10~~6.32$