# What is the length of the hypotenuse of a right triangle if the two other sides are of lengths 8 and 10?

Jan 10, 2016

$2 \sqrt{41} \mathmr{and} 12.806$

#### Explanation:

Use the famous pythagoras theorem

${a}^{2} + {b}^{2} = {c}^{2}$

Here a=8 and b=10 (or vice versa)

so $c = \sqrt{{8}^{2} + {10}^{2}}$

$c = \sqrt{164}$

$c = 2 \sqrt{41} \mathmr{and} 12.806$