What is the length of the radius and the coordinates of the center of the circle defined by the equation #(x+7)^2+(y-3)^2=121#?

2 Answers
Jul 6, 2017

In

#(x - p)^2 + (y - q)^2 = r^2#

The radius is given by #r# and the centre by #(p, q)#. Hence, our centre is #(-7, 3)# and the radius is #11#. The graph of the relation confirms.

graph{(x+ 7)^2 + (y - 3)^2 = 121 [-10, 10, -5, 5]}

Hopefully this helps!

Jul 6, 2017

Answer:

Radius is #11# and coordinates of center are #(-7,3)#

Explanation:

Equation of a circle whose center is #(h,k)# and radius is #r# is

#(x-h)^2+(y-k)^2=r^2#

As the equation #(x+7)^2+(y-3)^2=121# can be written as

#(x-(-7))^2+(y-3)^2=11^2#

Radius is #11# and coordinates of center are #(-7,3)#