What is the limit as x approaches infinity of 1.001^x1.001x?

1 Answer
Dec 18, 2014

its +oo+. (I am assuming you mean xx approaches positive infinity)

You can find this simply by looking at the graph of the function. You first have to notice that it's an exponential function (a^xax). You know this by noticing that there's an xx in the exponent. For exponential functions, there are two possible forms.

0 < a < 1:
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1 < a
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In this case a = 1.001a=1.001, which is bigger than 1
=> The function looks like the second function.

When x \to +oox+, the function also keeps rising. The function also goes to +oo+, thus:

lim_{x \to +oo} 1.001^x = +oo