# What is the trigonometric form of 12 e^( ( 5 pi)/2 i ) ?

Dec 12, 2016

Trigonometric form of 12e^(((5pi)/2i) is $12 \cos \left(\frac{5 \pi}{12}\right) + i 12 \sin \left(\frac{5 \pi}{2}\right)$

#### Explanation:

The trigonometric form of a complex number $z = r {e}^{i \theta}$ is

$z = r \cos \theta + i r \sin \theta$

Hence trigonometric form of 12e^(((5pi)/2i) is

$12 \cos \left(\frac{5 \pi}{12}\right) + i 12 \sin \left(\frac{5 \pi}{2}\right)$