# What is the trigonometric form of  13 e^( ( pi)/12 i ) ?

$13 {e}^{\frac{\pi}{12} i} = 13 \left(\cos \left(\frac{\pi}{12}\right) + i \sin \left(\frac{\pi}{12}\right)\right)$
${e}^{i x} = \cos x + i \sin x$
$13 {e}^{\frac{\pi}{12} i} = 13 \left(\cos \left(\frac{\pi}{12}\right) + i \sin \left(\frac{\pi}{12}\right)\right)$