# What is the trigonometric form of 8 e^( (3pi)/2 i ) ?

$8 {e}^{\frac{3 \pi}{2} i} = - 8 i$
Trigonometric form of $8 {e}^{\frac{3 \pi}{2} i}$ is
$8 \left(\cos \left(\frac{3 \pi}{2}\right) + i \sin \left(\frac{3 \pi}{2}\right)\right)$
= 8(0+ixx(-1)=-8i#