Question

What is the trigonometric form of `8 e^( (3pi)/2 i )`?

Answer 1

`8e^((3pi)/2i)=-8i`

Explanation:

Trigonometric form of `8e^((3pi)/2i)` is

`8(cos((3pi)/2)+isin((3pi)/2))`

= `8(0+ixx(-1)=`-8i#