# How do you write #F(x) = 3x^2 − 30x + 82# into vertex form?

##### 1 Answer

#### Explanation:

First we need to *complete the square* .

Now let's find the constant that will make

First we need to factor out that

Now we need to find that constant. To do that, we halve

**WAIT** We added a *real* equation is

Now our equaation is starting to look like vertex form!

Just to double check our work, we can graph both equations. If we did this right, they should look identical

graph{y=3x^2-30x+82}

graph{y=3(x-5)^2+7}

You have to zoom out a fair bit, but the graph are the same. Good job! We were right.