What is the vertex form of #y=-2x^2+17x+13 ?

1 Answer
Dec 29, 2015

The co-ordinate of vertex is # (4.25,49.125)#

Explanation:

The general form of Parabola is #y=a*x^2+b*x+c#
So here #a=-2 ; b=17 ; c=13#
We know the x co-ordinate of the vertex is # (-b/2a)#
Therefore the x co-ordinate of the vertex is # (-17/-4)# or #4.25#
Since the parabola passes through vertex the y co-ordinate will satisfy the above equation. Now putting #x=17/4# the equation becomes #y=-2*17^2/4^2+17*17/4+13# or #y =49.125#
Thus the co-ordinate of vertex is # (4.25,49.125)#[answer]