# What is the vertex form of y=2x^2 -452x-68 ?

Oct 14, 2017

vertex $= \left(113 , - 25606\right)$

#### Explanation:

$y = 2 {x}^{2} - 452 x - 68$

vertex form: $y = a {\left(x - h\right)}^{2} + k$ where $\left(h , k\right)$ is the vertex

$y = 2 \left({x}^{2} - 2 \cdot 113 \cdot x + 12769\right) - 25538 - 68$

$y = 2 {\left(x - 113\right)}^{2} - 25606$

$\implies$ vertex $= \left(113 , - 25606\right)$