What is the vertex form of y=2x^2+8x-5?
1 Answer
Aug 22, 2016
y=2(x+2)^2-13
Explanation:
Given -
y=2x^2+8x-5
Find the vertex
x=(-b)/(2a)=(-8)/(2xx 2)=(-8)/4=-2
At
y=2(-2)^2+8(-2)-5=8-16-5=-13
Quadratic equation in vertex form is -
y=a(x-h)^2+k
Where -
a=2
h=-2
k=-13
Plug in the values
y=2(x+2)^2-13