What is the vertex form of $y=2x^2+8x-5$ ?

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Answer 1 · 2016-08-22T07:10:22

$y=2(x+2)^2-13$

Given -

$y=2x^2+8x-5$

Find the vertex

$x=(-b)/(2a)=(-8)/(2xx 2)=(-8)/4=-2$

At $x=-2$

$y=2(-2)^2+8(-2)-5=8-16-5=-13$

Quadratic equation in vertex form is -

$y=a(x-h)^2+k$

Where -

$a=2$
$h=-2$
$k=-13$

Plug in the values

$y=2(x+2)^2-13$

What is the vertex form of y=2x^2+8x-5y=2x^2+8x-5?