# What is the vertex form of y= 6x^2 + 12x – 48 ?

Dec 31, 2015

$y = 6 {\left(x + 1\right)}^{2} - 54$

#### Explanation:

First simplify the expression
$y = 6 \left({x}^{2} + 2 x - 8\right)$
Then use completing the square
$y = 6 \left({\left(x + 1\right)}^{2} - 9\right)$
$y = 6 {\left(x + 1\right)}^{2} - 54$
The vertex is $\left(- 1 , - 54\right)$