What is the vertex form of #y= (x+1)(x-12)#? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Evan Jun 3, 2018 #y=(x-11/2)^2-85/2# Explanation: #y=(x+1)(x-12)# Expand, #y=x^2-11x-12# Make a perfect square, #y=x^2-11x+(-11/2)^2-(-11/2)^2-12# Simplify, #y=(x-11/2)^2-85/2#, where the vertex is #(11/2,-85/2)# :D Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1399 views around the world You can reuse this answer Creative Commons License