# What is the vertex form of y=x^2 + 3x - 10 ?

In Vertex form: $y = {\left(x + \frac{3}{2}\right)}^{2} - \frac{49}{4}$
$y = {x}^{2} + 3 x - 10 = {\left(x + \frac{3}{2}\right)}^{2} - \frac{9}{4} - 10 = {\left(x + \frac{3}{2}\right)}^{2} - \frac{49}{4}$ Comparing with general vertex form $y = a {\left(x - h\right)}^{2} + k$ we get vertex is at $\left(h , k\right) \mathmr{and} \left(- \frac{3}{2} , - \frac{49}{4}\right)$ graph{x^2+3x-10 [-40, 40, -20, 20]}[Ans]