Question

What is the vertex form of `y= x^2+7x-2`?

Answer 1

Vertex form is `y=(x+7/2)^2-57/4` and vertex is `(-3 1/2,-14 1/4)`

Explanation:

`y=x^2+7x-2`

= `x^2+2×7/2×x+(7/2)^2-(7/2)^2-2`

= `(x+7/2)^2-49/4-2`

= `(x+7/2)^2-57/4`

Hence, vertex form is `y=(x+7/2)^2-57/4` and vertex is `(-7/2,-57/4)` or `(-3 1/2,-14 1/4)`