# What is the vertex form of y=x^2-8x+3 ?

Apr 14, 2018

The vertex form of equation is $y = {\left(x - 4\right)}^{2} - 13$

#### Explanation:

$y = {x}^{2} - 8 x + 3 \mathmr{and} y = {x}^{2} - 8 x + 16 - 16 + 3$ or

$y = {\left(x - 4\right)}^{2} - 13$ . Comparing with vertex form of

equation f(x) = a(x-h)^2+k ; (h,k) being vertex we find

here $h = 4 , k = - 13 \therefore$ Vertex is at $\left(4 , - 13\right)$ and

The vertex form of equation is $y = {\left(x - 4\right)}^{2} - 13$

graph{x^2-8x+3 [-40, 40, -20, 20]}