What is the vertex of  y=x^2-4x+3 ?

Jan 4, 2016

The x-coordinate can be found using a simple formula ...

Explanation:

The general form of a quadratic is $y = a {x}^{2} + b x + c$

For this problem, $a = 1 , b = - 4 , c = 3$

$x = \frac{- b}{2 a} = - \frac{- 4}{2 \times 1} = 2$

Now that we now the x-coordinate of the vertex is $2$, insert it into the equation to find y ...

$y \left(2\right) = {2}^{2} - 4 \left(2\right) + 3 = - 1$

Vertex $= \left(2 , - 1\right)$

hope that helped